Problem
A strobogrammatic number is a number that looks the same when rotated 180 degrees (looked at upside down).
Find all strobogrammatic numbers that are of length = n.
Example:
Input: n = 2
Output: ["11","69","88","96"]
</>复制代码
class Solution {
public List findStrobogrammatic(int n) {
List res = new ArrayList<>();
if (n == 0) return res;
if (n == 1) return Arrays.asList("0", "1", "8");
Map map = new HashMap();
map.put("0", "0");
map.put("1", "1");
map.put("6", "9");
map.put("8", "8");
map.put("9", "6");
dfs(map, new char[n], 0, n, res);
return res;
}
private void dfs(Map map, char[] buffer, int index, int n, List res) {
// when index just passed the mid point, (n+1)/2 works for both odd and even
if (index == (n+1)/2) {
res.add(String.valueOf(buffer));
return;
}
for (char ch: map.keySet()) {
if (index == 0 && n > 1 && ch == "0") continue;
if (index == n/2 && (ch == "6" || ch == "9")) continue;
buffer[index] = ch;
buffer[n-1-index] = map.get(ch);
dfs(map, buffer, index+1, n, res);
}
}
}
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