[LeetCode] 448. Find All Numbers Disappeared in an

X_AirDu 发布于2019-08-16 14:28 / 3373人阅读

Problem

Given an array of integers where 1 ≤ a[i] ≤ n (n = size of array), some elements appear twice and others appear once.

Find all the elements of [1, n] inclusive that do not appear in this array.

Could you do it without extra space and in O(n) runtime? You may assume the returned list does not count as extra space.

Example:

Input:
[4,3,2,7,8,2,3,1]

Output:
[5,6]

Solution

class Solution {
    public List findDisappearedNumbers(int[] nums) {
        List res = new ArrayList<>();
        if (nums == null || nums.length == 0) return res;
        for (int i = 0; i < nums.length; i++) {
            int index = nums[i] > 0 ? nums[i]-1 : -nums[i]-1;
            if (nums[index] < 0) continue;
            nums[index] *= -1;
        }
        for (int i = 0; i < nums.length; i++) {
            if (nums[i] > 0) res.add(i+1);
        }
        return res;
    }
}

超融合服务器私有云 FIND_IN_SET Disappeared Numbers LeetCode

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