Problem
Given a singly linked list L: L0→L1→…→Ln-1→Ln,
reorder it to: L0→Ln→L1→Ln-1→L2→Ln-2→…
You may not modify the values in the list"s nodes, only nodes itself may be changed.
Example 1:
Given 1->2->3->4, reorder it to 1->4->2->3.
Example 2:
Given 1->2->3->4->5, reorder it to 1->5->2->4->3.
Solution</>复制代码
class Solution {
public void reorderList(ListNode head) {
if (head == null || head.next == null) return;
ListNode fast = head, slow = head.next, split = head;
while (fast != null && fast.next != null) {
split = slow; //to split slow to next half
fast = fast.next.next;
slow = slow.next;
}
//1 2 3 4 5
//3, 3, 2 (fast, slow, split)
//5, 4, 3 (fast, slow, split)
//1 2 3 4
//3, 3, 2
split.next = null;
ListNode l2 = reverse(slow);
ListNode l1 = head;
while (l2 != null) {
ListNode n1 = l1.next;
ListNode n2 = l2.next;
l1.next = l2;
l2.next = n1;
l1 = n1;
l2 = n2;
}
return;
}
private ListNode reverse(ListNode node) {
ListNode pre = null;
while (node != null) {
ListNode next = node.next;
node.next = pre;
pre = node;
node = next;
}
return pre;
}
}
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