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  • leetcode198,213 house robber

    House Robber I You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is tha...

    whidy 评论0 收藏0
  • [LeetCode] House Robber I II

    House Robber I Problem You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them...

    qpal 评论0 收藏0
  • [Leetcode] House Robber 打家劫舍

    House Robber I You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is tha...

    golden_hamster 评论0 收藏0
  • leetcode 198 House Robber

    题目详情 You are a professional robber planning to rob houses along a street. Each house has a certain amount of money stashed, the only constraint stopping you from robbing each of them is that adjacent ...

    jzman 评论0 收藏0
  • [LintCode/LeetCode] House Robber II

    ... tonight without alerting the police. Notice This is an extension of House Robber. Example nums = [3,6,4], return 6 Note 因为取了队首就不能取队尾,所以对dp数组循环两次,一个从0取到len-2,一个从1取到len-1,比较两次循环后队尾元素,取较大者。注意,...

    OnlyLing 评论0 收藏0
  • LeetCode[337] House Robber III

    LeetCode[337] House Robber III The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only ...

    Dr_Noooo 评论0 收藏0
  • [LintCode/LeetCode] House Robber III

    ...来进行划分的。 Solution public class Solution { public int houseRobber3(TreeNode root) { int[] A = dfs(root); return Math.max(A[0], A[1]); } public int[] dfs(TreeNode root) { ...

    macg0406 评论0 收藏0
  • leetcode337. House Robber III

    题目要求 The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only one parent house. After a t...

    AlphaWallet 评论0 收藏0
  • LeetCode 337. House Robber III

    Description The thief has found himself a new place for his thievery again. There is only one entrance to this area, called the root. Besides the root, each house has one and only one parent house. Af...

    ymyang 评论0 收藏0
  • leetcode 部分解答索引(持续更新~)

    ...tock 167 Two Sum II - Input array is sorted 169 Majority Element 198 House Robber(03-25更新) 217 Contains Duplicate 219 Contains Duplicate II 268 Missing Number 283 Move Zeroes 414 Third Maximum Num...

    leo108 评论0 收藏0
  • LeetCode 攻略 - 2019 年 7 月上半月汇总(55 题攻略)

    ... 191 - 位1的个数(number-of-1-bits) ✔ 198 - 打家劫舍(house-robber) ✔ 202 - 快乐数(happy-number) ✔ 203 - 移除链表元素(remove-linked-list-elements) ✔ 204 - 计数质数(count-primes) ✔ 205 - 同构字符串(isomorphic-strings) ✔ 206 - ...

    warmcheng 评论0 收藏0
  • react-native, react-navigation, redux 学习笔记

    ...spatch(addmoney(earn.money + 1000000)) return dispatch(setLastJob(robber)) } } // 定义一个赚钱的方式2,建材转移者 export function moveBrick(){ return (dispatch, getState) => { console.log(...

    妤锋シ 评论0 收藏0
  • 前端 | 每天一个 LeetCode

    ...ts ↗ Easy 202 快乐数 Happy Number ↗ Easy 198 打家劫舍 House Robber ↗ Easy 191 位 1 的个数 Number of 1 Bits ↗ Easy 190 颠倒二进制位 Reverse Bits ↗ Easy 189 旋转数组 Rotate Array ↗ Easy 172 阶乘后的零 Factorial Tr...

    张汉庆 评论0 收藏0
  • LeetCode 攻略 - 2019 年 7 月下半月汇总(100 题攻略)

    ... 191 - 位1的个数(number-of-1-bits) ✔ 198 - 打家劫舍(house-robber) ✔ 202 - 快乐数(happy-number) ✔ 203 - 移除链表元素(remove-linked-list-elements) ✔ 204 - 计数质数(count-primes) ✔ 205 - 同构字符串(isomorphic-strings) ✔ 206 - ...

    tain335 评论0 收藏0
  • LeetCode 精选TOP面试题【51 ~ 100】

    ...)+动规) [198. 打家劫舍](https://leetcode-cn.com/problems/house-robber/)(动规) [136. 只出现一次的数字](https://leetcode-cn.com/problems/single-number/)(异或运算) [69. Sqrt(x)](https://leetcode-cn.com/problems/sqr...

    Clect 评论0 收藏0

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